20y^2+37y-14=0

Solution for 20y^2+37y-14=0 equation:

20y^2+37y-14=0

a = 20; b = 37; c = -14;
Δ = b2-4ac
Δ = 372-4·20·(-14)
Δ = 2489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{2489}}{2*20}=\frac{-37-\sqrt{2489}}{40}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{2489}}{2*20}=\frac{-37+\sqrt{2489}}{40}
$